Many readers have asked questions regarding the implication of an E-cat. If we could give them numbers to relate to. Well, you asked for it and we listened. To get a clearer view of the implications of the E-Cat we did some number crunching to find out what the E-Cat is really about in comparison to Oil as a major energy source competitor.
Photo credits AZRainman under Creative Commons.
First of all if we take a look at the energy density of oil, wich can be found here Energy Density
OilED=46.3 MJ/kg
This number has not been adjusted for the weight of the oxygen needed in order to combust the Oil, but it is okay since the approximation will be fairly accurate anyway. Now, we would like to find the NiH systems energy density whereby we have to do some calculations. There are only 2 isotopes of Nickel that transmutes into Copper through proton fusion and that is Ni62 and Ni64 by which the abundancy of Ni62 outscores Ni64 by a factor 4 so we focus on the Ni62+p->Cu63 reaction as the main contributor to the energy density. What is clear from statements by Andrea Rossi is that they enrich the Nickel so they at least get rid of the Ni58 isotope which is the most abundant of all the nickel isotopes. For simplicity we will from now on only consider pure Ni62.
The weight of Ni62 is,
m(Ni62)=61.928345115 AMU,
m(p)=1.00782503207 AMU
where AMU is the atomic mass unit which in kg is,
1 AMU=1.66054*10^-27kg. The mass of Cu63 is,
m(Cu63)=62.929597474 AMU.
We can now find the energy received through the proton fusion by subtracting startmass from endmass.
m(Ni62)+m(p)-m(Cu63)=61.928345115 AMU+1.00782503207 AMU-62.929597474 AMU=0.00657267 AMU.
Converted to energy through E=mc^2 we get,
E(Ni62+p->Cu63)=6.12241 MeV.
To get a feeling for this number this can be compared to when Hydrogen gas is burned with oxygen whereby the 2.96eV is released per Hydrogen molecule or 1.48eV per hydrogen atom. So in comparison we see that the nuclear fusion reaction releases more than one million times the energy compared to one of the most energy rich chemical reactions. Now Nickel is of course heavier than both hydrogen and oxygen combined so we will have to add some more calculations in order to receive the energy density of the reaction.
The energy density can be received by the dividing the released energy by the mass of the endproduct, which in this case is Cu63,
Ni62HED=6.12241 MeV/62.929597474 AMU=9.38704*10^6 MJ/kg.
We can see that even if we add the cost of 140 MJ/kg for electrolysis of the hydrogen this would only effect the 4th decimal. Now compare this with Oil and we get a energy factor of
ECatvsOil=Ni62HED/OilED=202744.
Now that is an astonishing number the E-Cat gives us 200,000 times the ED of Oil. What does that mean in more understandable figures?
Take a car comparison:
Let the car consume 1l/10km and note that although the E-Cat produces heat a heat engine and a combustion engine have pretty much the same conversion efficiencies (around 20-30%).
This means (taken diesel as fuel with ED=46.2MJ/kg and density of 0.807kg/l) the car gets a distance of
CarOilDist=12.4km/kg,
while the E-Cat would get
CarECatDist=2.5 million km.
Yes you saw right 2.5 million km, if we assume a car life is about 500,000km then only 200grams of Ni62H is needed in order to do the full distance. No more gas stations there.
Price wise Nickel is traded at $21/kg so the Ni62H cost is negligible, bar of course, the cost of the enrichment process.
Food for thought:
Which car would you rather have? An E-cat driven or a “modern” car run by oil? Keep in mind that an e-cat driven car are several years away as a viable solution. Consider the first combined heat and powered (CHP) modules from Defkalion Green Technologies – the T-ford in terms of efficiency and design.
Please continue to send your questions to us at [email protected]
Thank you.


Peter
June 29, 2011
Do they ever say how much they enrich the nickel? I do not think they get 100% active nickel.
Even if they do not enrich the nickel at all it would only lower the output per mass by a factor of two, so if this is really undergoing a nuclear reaction it is still amazingly more efficient than what we are using now.
Peter
June 29, 2011
Oops, that should say “it would only lower the output by two orders of magnitude”
admin
June 29, 2011
Hi, Peter
As of now we don’t know – it is part of Andrea Rossi’s secret. We do know, though, that they do enrich the nickel and that Andrea Rossi has said that Ni58 does not work. If that is because it creates radiation or if it simply does not react with hydrogen we do not know. When it comes to energy density it really does not matter because even if they separate the nickel and only keep Ni62 and maybe Ni64, with abundancies about 4% and 1% respectively, they will be able to sell back the other isotopes, because in all other applications Ni62 and Ni64 will be irrelevant. When it comes to total amount of energy reserves in nickel it does matter though, it will decrease that amount by a factor of 20 (5%) of course. With todays energy consumption nickel will last for billions of years, though, so when the E-Cat hit the market we can forget about the energy problem.
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